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Question

In the situation shown in figure, the tension in the string connecting the two blocks will be (string is massless and frictional force is negligible)
1202973_3a36b850e6d0418aa2f6bad0f0eb583e.png

A
20 N
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B
25 N
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C
30 N
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D
18 N
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Solution

The correct option is C 30 N
In this situation shown in the figure.
The transmission in the string connecting the two blocks will be
In first block
Applying force=10N
Let, the tension between two blocks=T
Now,
10T=4f(1)
(where F be the acceleration of the system )
And
30T=6f(2)
Now solving the equation and we will get,
10T=4f30T=6f
+20=2ff=10m/s210T=4×10T=30N


1221341_1202973_ans_6f32c35969574411816d7ab7033fe1e1.png

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