Question

In the solar system, the Sun is in the focus of the system for Sun-Earth binding system. Then the binding energy for the system will be $($given that radius of the Earth's orbit around the Sun is $1.5\times {10}^{11}$ m and mass of Earth is $6\times {10}^{24}kg$ $)$

$Massofthesunis{10}^{30}kg$

• A. $2.7\times {10}^{33}J$
• B. $5.4\times {10}^{33}J$
• C. $2.7\times {10}^{30}J$
• D. $5.4\times {10}^{30}J$

Answer 1

Answer: (A)

$2.7\times {10}^{33}J$

Binding energy is given by,
$B.E.=\frac{GMm}{R}$
Where,
M$=$ mass of the Sun $=$ ${10}^{30}$ kg
m $=$ mass of the Earth $=6\times {10}^{24}$ kg
$R=1.5\times {10}^{11}$ m
Binding energy of the system is given by,
$B.E.=\frac{6.67\times {10}^{-11}\times {10}^{30}\times 6\times {10}^{24}}{1.5\times {10}^{11}}=2.7\times {10}^{33}$ J