Question

IN the Solvay process, can we obtain sodium carbonate directly by treating the solution containing $(N{H}_4{)}_{2}C{O}_3$ with sodium chloride? Explain.

Answer 1

No, it is not.

$(N{H}_4{)}_{2}C{O}_3$ reacts with NaCl as

$(N{H}_4{)}_{2}C{O}_3+2NaCl\rightleftharpoons N{a}_{2}C{O}_3+2N{H}_{4}Cl$

Because the products obtained $N{a}_{2}C{O}_{3}andN{H}_{4}Cl$ are highly soluble and the equilibrium will not shift in forward direction.
That's Why in the Solvay process, we cannot obtain sodium carbonate directly by treating the solution containing$(N{H}_4{)}_{2}C{O}_3$ with sodium chloride.