Question

In the square $ABCD$ show that the two triangles $ABC$ and $ADC$ are congruent to each other

Answer 1

we have,

In the square $ABCD$

Construct:- Draw diagonal $AC$then makes two $\Delta ABC\&\Delta ADC$

Prove that:-$\Delta ABC\cong \Delta ADC$

Proof:- In $\Delta ABC\&\Delta ADC$

$AB=DC\left(sidesofsquare\right)$

$AD=BC\left(sidesofsquare\right)$

$AC=AC\left(common\right)$

Hence, $\Delta ABC\cong \Delta ADC$ $\left(bySSScongruency\right)$

Hence proved.