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Question

In the square frame of side l of metallic rods, corners A and C are maintained at T1 and T2 respectively. The rate of heat flow from A to C is ω. If A and D are instead maintained at T1 and T2 respectively, the total rate of heat flow is (x3)ω. Find 'x'.
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Solution

Thermal Resistance R=LKA where L is the length of conductor, K is the thermal conductivity and A is the cross-sectional area.
If A and C are maintained at temp T1 and T2 respectively, we can consider RAB and RBC as being in series.
RACupper=RAB+RBC=LKA+LKA=2LKA
RAClower=RAD+RDC=LKA+LKA=2LKA
Both RACupper and RAClower are in parallel.
1RAC=1RACupper+1RAClower
RAC=LKA
(dQdt)AC=T2T1RAC=(T2T1)KAL=ω as given
When A and D are maintained at T1 and T2 respectively.
RAB, RBC and RCD will be in series.
1(RAD)eq=(RAB+RBC+RCD)||RAD
1(RAD)eq=(LKA+LKA+LKA)||(LKA)
(RAD)eq=3LKA×LKA4LKA=3L4KA
(dQdt)AD=T2T1(RAD)eq=T2T13L4KA=43ω

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