Question

In the square root of 1296, what would be the highest power of 3 ?

• A. 0.0
• B. 4
• C. 2
• D. 1

Answer 1

The correct option is C 2

We can prime factorise to find the highest power of 3 in square root of 1296


So we get $1296=3\times 3\times 3\times 3\times 2\times 2\times 2\times 2$
$1296=3^4\times 2^4$
$\sqrt{1296}=\sqrt{3^4\times 2^4}=3^2\times 2^2$

So the highest power of 3 is 2.