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Question

In the steady state of temperature at the end of a copper rod of length 25cm and area of cross-section 1.0cm2 are 125oC and 0oC respectively. Calculate the temperature gradient, rate of heat flow and the temperature at a distance 10cm from the hot end. [K for copper =9.2×103kilocal/moCs]

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Solution

l=25cm=0.25mA=1cm2=1×104m2K=9.2×103kcal/moCs
125025×1029.2×103×1×104=x015×1029.2×103×1×10412525=x15x=75

Temperature gradient (at 10cm from hotter end)
=7500.15K/m=500K/m

853226_761768_ans_344effe6681046c8a1caa282cc38e32b.png

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