In the steady state, the two ends of a metel rod are at 30oC and 20oC. The temperature at the 60th cm is
A
22oC
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B
23oC
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C
24oC
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D
25oC
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Solution
The correct option is C24oC Given the rod is in steady state, and of one meter length. Temperature gradient is a constant. dTdx=c dT=cdx T=cx+a; Substituting the conditions that T(0) = 30 and T(100) = 20; T=−0.1x+30; putting T(60) we get T(60)=−6+30=24∘C