Question

In the steady state the two ends of a metre rod are at 30${}^o$C and 20${}^o$C , the temperature at the $40th$ cm from the end at higher temperature is

• A. ${22}^{o}C$
• B. ${26}^{o}C$
• C. ${25}^{o}C$
• D. ${24}^{o}C$

Answer 1

Answer: (B)

${26}^{o}C$

Substituting ${\theta }_1={30}^o$
${\theta }_2={20}^o$
$L=100$ & $l=60$
$\frac{{30}^o-{20}^o}{100}=\frac{\theta -{20}^o}{60}$
$\theta ={26}^o$