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Byju's Answer

Standard XII

Physics

Buoyant Force

In the stream...

Question

In the streamlined flow of a liquid, the power due to pressure difference between the ends of the tube is

equal to a product of pressure and volume of liquid flowing per second

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equal to a product of pressure and mass of liquid flowing per second

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equal to the product of radius and coefficient of viscosity

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equal to the product of pressure and velocity.

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Solution

The correct option is A equal to a product of pressure and volume of liquid flowing per second
for streamlined flow of liquid, $p o w e r = \frac{(P \times V)}{t}$

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In the streamlined flow of a liquid, the power due to pressure difference between the ends of the tube is

The correct option is A equal to a product of pressure and volume of liquid flowing per secondfor streamlined flow of liquid, power=(P×V)t

The correct option is A equal to a product of pressure and volume of liquid flowing per second
for streamlined flow of liquid, $p o w e r = \frac{(P \times V)}{t}$