Question

In the structure of diamond, carbon atoms appears at:

• A. $0,0,0$ and $\frac{1}{2},\frac{1}{2},\frac{1}{2}$
• B. $\frac{1}{4},\frac{1}{4},\frac{1}{4}$ and $\frac{1}{2},\frac{1}{2},\frac{1}{2}$
• C. $0,0,0$ and $\frac{1}{4},\frac{1}{4},\frac{1}{4}$
• D. $0,0,0$ and $\frac{3}{4},\frac{3}{4},\frac{3}{4}$

Answer 1

The correct option is A $0,0,0$ and $\frac{1}{2},\frac{1}{2},\frac{1}{2}$

In the structure of diamond, carbon atoms appears at $0,0,0$ and $\frac{1}{2},\frac{1}{2},\frac{1}{2}$.The coordinates $0,0,0$ represents C atoms present at corners and the coordinates $\frac{1}{2},\frac{1}{2},\frac{1}{2}$ represents the C atom present at body centre. These coordinates corresponds to body centered cubic unit cell (bcc).