Question

In the sulphur estimation, $0.751$ g of an organic compound gave $0.3184$ g of barium sulphate. What is the percentage of sulphur in the compound?

• A. $5.8$%
• B. $91.32$%
• C. $53.2$%
• D. $69$%

Answer 1

The correct option is A $5.8$%

mass of organic compound = 0.751

mass of barium sulphate = 0.3184

molar mass barium sulphate = 233 gm

0,3184 barium sulphate containe = $\frac{32}{233}\times 0.3184=0.043$

percentage of sulpur = $\frac{0.043}{0.751}\times 100$

$=5.8$