1
Question
In the survey of population of 600 student . it is found that 250 can be speck English (E), 210 can speck Hindi(H), 120 speck can be Tamil(T) If 100 people can speck both E and H , 80 can be speck both E and T , 5 can be speck both H and T , 20 can be speck all three langauges , find the number of people who can speck E but not H or T . Find also the number of the people who can speck neither E nor H nor T.
Open in App
Solution
Number of students who can speak both E and H=100Number of students who can speak both E and T=80
Total number of Students who can speak all H,E,T=20Total number of students who can speak E=250
Hence, total number of students who can speak only E but not H or T=250−100−80=70
Total student =600Total number of students who can speak H=210Total number of students who can speak E=250
Total number of students who can speak T=120
Total number of students who can speak neither E nor H nor T=600−250−210−120⇒20
Number of students who can speak both E and H=100
Number of students who can speak both E and T=80
Total number of Students who can speak all H,E,T=20
Total number of students who can speak E=250
Hence, total number of students who can speak only E but not H or T=250−100−80=70
Total student =600
Total number of students who can speak H=210
Total number of students who can speak E=250
Total number of students who can speak T=120
Total number of students who can speak neither E nor H nor T=600−250−210−120⇒20
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
