In the system, $L a C l_{3} (S) + H_{2} O (g) + h e a t ⇌ L a C l O (s) + 2 H C l (g),$ equilibrium is established. More water vapour is added to restablish the equilibrium. The pressure of water vapour is doubled. The factor by which pressure of HCI is changed is:

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$\sqrt{2}$

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$\sqrt{3}$

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$\sqrt{5} L I$

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Solution

The correct option is B
$\sqrt{2}$

$L a C l_{3 (s)} + H_{2} O_{(} g) + h e a t ⇌ L a C l O_{(s)} + 2 H C l_{(g)} k_{p} = \frac{(p_{H C l})^{2}}{p_{H C l}}$

$p_{H C l} = \sqrt{k_{p} \times p_{H C l}} n e w p_{H C l} = \sqrt{k_{p} \times p_{H C l} \times 2}$

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