In the system shown in figure pulley is smooth. String is massless and inextensible. Find acceleration of the system a, tensions T1andT2.(g=10m/s2). Report the sum of their values.
A
20
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B
10
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C
20/3
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D
40
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Solution
The correct option is C20/3 Here, net pulling force will be: Weight of 4kg and 6kg blocks on one side and weight of 2kg block on the other side. Therefore, a=NetpullingforceTotalmass =(6×10)+(4×10)−(2)(10)6+4+2 =203m/s2 For T1, let us consider FBD of 2kg block. Writing equation of motion, we get T1−20=2a or T1=20+2×203=1003N For T2, we may consider FBD of 6kg block. Writing equation of motion, we get 60−T2=6a T2=60−6a =60−6(203) =20N