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Question

In the system shown in figure pulley is smooth. String is massless and inextensible. Find acceleration of the system a, tensions T1andT2. (g=10m/s2). Report the sum of their values.
245500_5c25e28079914f618b23bf21dd9a234b.png

A
20
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B
10
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C
20/3
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D
40
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Solution

The correct option is C 20/3
Here, net pulling force will be:
Weight of 4kg and 6kg blocks on one side and weight of 2kg block on the other side.
Therefore,
a=NetpullingforceTotalmass
=(6×10)+(4×10)(2)(10)6+4+2
=203m/s2
For T1, let us consider FBD of 2kg block. Writing equation of motion, we get
T120=2a
or T1=20+2×203=1003N
For T2, we may consider FBD of 6kg block. Writing equation of motion, we get
60T2=6a
T2=606a
=606(203)
=20N
255927_245500_ans_dee038684f6f4756af9dfaa33d6333ef.png

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