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In the system shown in the figure at some instant acceleration of pulley was  $$10 m/sec^{2}$$ in upward direction. At that instant spring was in its natural length. If acceleration of block A and B are $$a_{A}\ and\ a_{B}$$ at that instant then :  $$\left ( Given\ m_{A}=10 kg, m_{B}= 20 kg, g =10 m/sec^{2}, pulley\ is\ light\ and\ smooth\right )$$


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A
aA=103m/sec2upwardaB=103m/sec2downward
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B
aA=aB=5 m/sec2upward
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C
aA=aB=10 m/sec2downward
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D
None of these
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Solution

The correct option is C $$a_{A}=a_{B}=10\ m /sec^{2} downward$$
Answer is C
Since the spring is in its natural length, then tension in the string is zero. This implies that blocks are in the free fall state and
$$a_A= a_B= g  \ with\  direction\  downwards$$

Physics

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