In the system shown in the figure, the acceleration of $1 k g$ mass is :

\frac{g}{4} d o w n w a r d s

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\frac{g}{2} d o w n w a r d s

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\frac{g}{2} u p w a r d s

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\frac{g}{4} u p w a r d s

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Solution

The correct option is C $\frac{g}{2} u p w a r d s$
FBD for 1 kg object,
$T - g = a$
FBD for 4 kg object,
$4 g - 2 T = 2 a$
Comparing above equations,

$a = \frac{g}{2} m s^{- 2}$ (upwards)

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Similar questions

In the system shown in figure, the acceleration of 1kg mass is

g = 10 m / s^{2}

m_{a} = 3 kg

m_{b} = 1 kg

(g = 10 m s^{- 2})

g = 10 m / s^{2})

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