In the system shown m1>m2. System is held at rest by thread BC. Just after lower thread is Burnt,
A
Acceleration of m2 is upward
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B
Magnitude of acceleration of both blocks will be (m1−m2m1+m2)g
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C
Acceleration of m1 will be equal to zero
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D
Magnitudes of acceleration of two blocks will be non-zero and unequal
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Solution
The correct options are A Acceleration of m2 is upward C Acceleration of m1 will be equal to zero Before burn, T=m1g & T=T1+m2g After burning the wire, Tension in the spring does not change instantaneously.
so, for m1 Fnet= T−m1g = 0 ∴am1=0 For m2 T1 becomes zero and m2 will have a non-zero acceleration ∴T′−m2g=m2a ⇒a=T′m2−g