You visited us 1 times! Enjoying our articles? Unlock Full Access!

Amino Acids

In the test f...

Question

In the test for iodine, $I_{2}$ is treated with sodium thiosulphate $(N a_{2} S_{2} O_{3})$
$(N a_{2} S_{2} O_{3}) + I_{2} ⟶ N a I + \dots \dots$

N a_{2} S_{4} O_{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N a_{2} S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{2} S

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{3} I S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $N a_{2} S_{4} O_{6}$
Option (A) is correct.In the test for iodine, $I_{2}$ is treated with sodium thiosulphate forms sodium tetrathionate.

$2 N a_{2} S_{2} O_{3}$ $+ I_{2} ⟶ 2 N a I$ + $N a_{2} S_{4} O_{6}$

Suggest Corrections

Similar questions

(N a_{2} S_{2} O_{3} \cdot 5 H_{2} O)

2 N a_{2} S_{2} O_{3} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}

N a_{2} S_{2} O_{3}

N a_{2} S

S + N a O H \to N a_{2} S_{2} O_{3} + N a_{2} S

N a I

N a_{2} S O_{4}

N a_{2} S_{2} O_{3} + I_{2} + N a O H \to N a I + N a_{2} S O_{4} + H_{2} O

N a I

A g N O_{3}

I_{2} + N a_{2} S_{2} O_{3} \to N a_{2} S_{4} O_{6} + N a I

N a_{2} S_{2} O_{3}

I_{2}

N a_{2} S_{4} O_{6}

N a I

Balance the following equations:
1. FeCl₃ + NH₄OH → Fe(OH)₃ + NH₄Cl
2. Na₂S₂O₃ + I₂ → Na₂S₄O₆ + NaI

Join BYJU'S Learning Program