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Standard XII

Chemistry

Concentration Terms

In the therma...

Question

In the thermal decomposition of $C_{2} H_{5} B r$ to $C_{2} H_{4}$ and $H B r$ , the pressure changed from an initial value of $200 m m H g$ to $390 m m H g$ at the end of the reaction. What fraction remained unchanged when the pressure of the mixture was $300 m m H g$ ?

0.47

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0.67

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0.12

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0.72

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Solution

The correct option is A $0.47$
The complete decomposition of $C_{2} H_{5} B r$ result in change of $390 - 200 = 190 m m$ $H g$ of pressure.
So, Change in pressure of $190 m m H g = 100$ % change
$1 m m$ of $H g$ pressure change results $= \frac{100}{190}$
$300 - 200$ i.e $10 m m$ of $H g$ pressure change results in $= \frac{100}{190} \times 100 = 52.63$ %
Fraction that reaction unchanged $= 1 - \frac{52.63}{100} = 0.47$

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In the thermal decomposition of C2H5Br to C2H4 and HBr, the pressure changed from an initial value of 200 mmHg to 390 mmHg at the end of the reaction. What fraction remained unchanged when the pressure of the mixture was 300 mmHg?

In the thermal decomposition of $C_{2} H_{5} B r$ to $C_{2} H_{4}$ and $H B r$ , the pressure changed from an initial value of $200 m m H g$ to $390 m m H g$ at the end of the reaction. What fraction remained unchanged when the pressure of the mixture was $300 m m H g$ ?