Question

In the trapezium ABCD shown below, AB and CD are parallel. Using the given measurements (in centimetres), find its area:

Answer 1

In ΔAPD, right-angled at P:

Also, PQ = DC = 6 cm

∴ AB = AP + PQ + PB = (3 + 6 + 3) cm = 12 cm

Now, in trapezium ABCD, the parallel sides are AB = 12 cm, DC = 6 cm and the height DP = 4 cm.

We know that the area of trapezium is half the product of the sum of its parallel sides and the distance between them.

∴ Area of trapezium ABCD =