In the trapezium ABCD shown below- if - ADC - 120- then find the measure in degrees of - DCB-

Given: ABCD is a trapezium. ⇒ BC ∥ AD nbsp; ⇒∠ ADC + ∠ DCB = 180^∘ (Interior angles on the same side of transversal DC) ⇒ 120^∘ + ∠ DCB = 180^∘ ⇒∠ DCB ...

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Standard VIII

Mathematics

Parallelogram and Its Properties

In the trapez...

Question

In the trapezium ABCD shown below, if $∠ A D C = 120^{\circ}$ , then find the measure (in degrees) of $∠ D C B$ .

60

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Solution

The correct option is A 60
Given: ABCD is a trapezium.

$\Rightarrow B C ∥ A D$

$\Rightarrow ∠ A D C + ∠ D C B = 180^{\circ} (Interior angles on the same side of$
$transversal DC)$

$\Rightarrow 120^{\circ} + ∠ D C B = 180^{\circ}$

$\Rightarrow ∠ D C B = 180^{\circ} - 120^{\circ}$

$\Rightarrow ∠ D C B = 60^{\circ}$

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In the trapezium ABCD shown below, if ∠ADC=120∘, then find the measure (in degrees) of ∠DCB. 60

The correct option is A 60Given: ABCD is a trapezium. ⇒BC∥AD ⇒∠ADC+∠DCB=180∘ (Interior angles on the same side of transversal DC) ⇒120∘+∠DCB=180∘ ⇒∠DCB=180∘−120∘ ⇒∠DCB=60∘

In the trapezium ABCD shown below, if $∠ A D C = 120^{\circ}$ , then find the measure (in degrees) of $∠ D C B$ .

60