In the triangle ABC, BD bisects angle B and is perpendicular to AC. If the lengths of the sides of the triangle are expressed in terms of x and y as shown, find the values of x and y.
In ΔABD and ΔCBD
BD=BD (common)
∠ADB=∠CDB(each900 )
∠ABD=∠CDB ( BD bisects angle B)
ΔABD≅Δ CDB (by a. s a)
→ 3x+1=5y-2 (cpctc )
→x=(5y−3)3......(1)
→ x+1=y+2 (cpctc)
→ x=y+1. .........(2)
from (1) and (2)
→ y-3=3(y+1)
→ 5y-3y=3+3
→ 2y=6
→ y=3
put y=3 in (2)
→ x=3+1
→ x=4