In the triangle above, calculate the average (arithmetic mean) of $x, y$ and $z$ .

30

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45

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60

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75

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90

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Solution

The correct option is C $60$
In the given figure, $x, y, z$ form the angles of a triangle.
We know, by Angle Sum Property of triangle, all the $3$ angles of a triangle is equal to $180$ degree.
$⟹ x + y + z = 180^{o}$
Then, Formula for average or arithmetic mean is:
$Mean =$ $\frac{Total value}{No. of variables/items}$ .
So, average of $x, y, z$ will be $\frac{180}{3} = 60$ .

Hence, option $C$ is correct.

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In the triangle above, calculate the average (arithmetic mean) of x,y and z.

In the triangle above, calculate the average (arithmetic mean) of $x, y$ and $z$ .