In the triangle above- the sine of x- is 0-6- What is the cosine of y- -

Given : sinx = 0.6 We know, x+y+90=180^o⇒ y=90 x Now, #160; cosy = cos(90 x) = sinx = 0.6 ...

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Standard XII

Mathematics

Conditional Identities

In the triang...

Question

In the triangle above, the sine of $x^{\circ}$ is $0.6$ . What is the cosine of $y^{\circ}$ ?

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Solution

Given : $sin x = 0.6$
We know, $x + y + 90 = 180^{o} \Rightarrow y = 90 - x$
Now, $cos y = cos (90 - x) = sin x = 0.6$

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In the triangle above, the sine of x∘ is 0.6. What is the cosine of y∘ ?

Given : sinx=0.6We know, x+y+90=180o⇒y=90−xNow, cosy=cos(90−x)=sinx=0.6

In the triangle above, the sine of $x^{\circ}$ is $0.6$ . What is the cosine of $y^{\circ}$ ?

Given : $sin x = 0.6$
We know, $x + y + 90 = 180^{o} \Rightarrow y = 90 - x$
Now, $cos y = cos (90 - x) = sin x = 0.6$