Question

In the triangle ACB Line AP divides the two triangles APB and ACP.

If Area of $\Delta$ APB = $24c{m}^2$ and Area $\Delta$ APB : Area of $\Delta$ APC = 4 : 7, find the area of $\Delta$ APC

• A. $42c{m}^2$
• B. $54c{m}^2$
• C. $36c{m}^2$
• D. $48c{m}^2$

Answer 1

The correct option is A

$42c{m}^2$

Area of $\Delta$ APB : Area of $\Delta$ APC = 4 : 7

Area of $\Delta$ APB = 4x and Area of $\Delta$ APC = 7x

4x = 24

$\Rightarrow$ x = 6

$\therefore$ Area of Triangle APC = 7x = 7$\times$6 = $42c{m}^2$