Question

In the Uranium radioactive series the initial nucleus is ${}_{92}^{238}U$ and the final nucleus is ${}_{82}^{206}Pb$. When the Uranium nucleus decays to lead, the number of $\alpha -particles$ emitted is _________ and the number of $\beta -particles$ emitted is _________.

Answer 1

${}_{92}^{238}U⟶{}_{82}^{206}Pb+x{\alpha }_2^{4L^{+}}+{}_{-1}^0{\beta }^{-}.y$

$x=\frac{238-206}{4}=8$

$y=\frac{92-(16+82)}{-1}=6$

$\alpha -$particle $=8$

$\beta -$particle $=6$