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Introduction to Atomic Structure

In the Uraniu...

Question

In the Uranium radioactive series the initial nucleus is $_{92}^{238} U$ and the final nucleus is $_{82}^{206} P b$ . When the Uranium nucleus decays to lead, the number of $α - p a r t i c l e s$ emitted is _ and the number of $β - p a r t i c l e s$ emitted is _.

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Solution

$_{92}^{238} U ⟶_{82}^{206} P b + x α_{2}^{4 L^{+}} +_{- 1}^{0} β^{-} . y$
$x = \frac{238 - 206}{4} = 8$
$y = \frac{92 - (16 + 82)}{- 1} = 6$
$α -$ particle $= 8$
$β -$ particle $= 6$

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