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Byju's Answer
Standard XII
Mathematics
General Term of Binomial Expansion
In the usual ...
Question
In the usual notation prove that
C
0
+
C
1
2
x
+
C
2
3
x
2
+
.
.
.
.
.
.
+
C
n
n
+
1
x
n
=
(
1
+
x
)
n
+
1
−
1
(
n
+
x
)
x
Open in App
Solution
If we take x from R.H.S to L.H.S the equations reduces to
C
0
x
+
C
1
x
2
2
+
C
2
x
3
3
+
.
.
.
.
+
C
n
x
n
+
1
n
+
1
=
(
1
+
x
)
n
+
1
−
1
n
+
1
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0
Similar questions
Q.
In the usual notations prove that
(
C
0
+
C
1
)
(
C
1
+
C
2
)
.
.
.
.
.
(
C
n
−
1
+
C
n
)
=
(
n
+
1
)
n
n
!
C
1
C
2
C
3
.
.
.
.
.
C
n
Q.
If
c
0
,
c
1
,
c
2
,
.
.
.
.
.
.
.
c
n
denote the coefficients in the expansion of
(
1
+
x
)
n
, prove that
(
c
0
+
c
1
)
(
c
1
+
c
2
)
.
.
.
.
.
.
.
(
c
n
−
1
+
c
n
)
=
c
1
c
2
.
.
.
c
n
(
n
+
1
)
n
|
n
–
–
.
Q.
If
c
0
,
c
1
,
c
2
,
.
.
.
.
.
.
.
c
n
denote the coefficients in the expansion of
(
1
+
x
)
n
, prove that
c
0
+
c
1
2
+
c
2
3
+
.
.
.
.
.
.
+
c
n
n
+
1
=
2
n
+
1
−
1
n
+
1
.
Q.
If
c
0
,
c
1
,
c
2
,
.
.
.
.
c
n
denote the coefficients in the expansion of
(
1
+
x
)
n
, prove that
c
0
+
c
1
2
+
c
2
3
+
.
.
.
.
.
+
c
n
n
+
1
=
2
n
+
1
−
1
n
+
1
.
Q.
c
0
,
c
1
,
c
2
denotes coefficents expansion of
(
1
+
x
)
n
, then
c
1
+
c
1
c
2
+
c
2
c
3
+
.
.
.
.
.
.
.
c
n
−
1
c
n
=
(
2
n
)
!
(
n
+
1
)
!
(
n
−
1
)
!
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