In the xy plane- the segment with end points 3-8 and -5-2 is the diameter of the circle- The point k- 10 lies on the circle forA- exactly one non integral kB- no value of kC- exactly one integral kD- two real values of k

The correct option is C exactly one integral k A(3, 8), B( 5, 2) and P(K, 10) PA =1/2AB ...

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Modulus of a Complex Number

In the xy pla...

Question

In the xy plane, the segment with end points (3, 8) and (–5, 2) is the diameter of the circle. The point (k, 10) lies on the circle for

no value of k

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exactly one integral k

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exactly one non integral k

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two real values of k

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Solution

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Similar questions

In the $x y$ plane, the segment with end points $(3, 8)$ and $(5, 2)$ is the diameter of the circle. The point $(k, 10)$ lies on the circle for:

x - y

(3, 8)

(- 5, 2)

(k, 10)

k x + (k + 1) y + (k - 1) z = 0

(k + 1) x + k y + (k + 2) z = 0

(k - 1) x + (k + 2) y + k z = 0

x^{2} + y^{2} + 5 K x + 2 y + K = 0

2 (x^{2} + y^{2}) + 2 K x + 3 y - 1 = 0, (K \in R),

P

Q

4 x + 5 y - K = 0

P

Q

k

5 x^{2} + (k + 1) x + k = 0

(1, 3)

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