In the year 2001, the number of malaria patients admitted in the hospitals of a state was 4375. Every year this number decreases by 8%. Find the number of patients in 2003.

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Solution

The number of malaria patients admitted in a hospital in 2001 = 4375
Rate of decrement of malaria patients = 8%
Time period = 2 yr [ $∵$ 2003-2001= 2 yr]
Let the number of patients in 2003 be A.
By using formula, $A = P {(1 - \frac{R}{100})}^{r}$
$= 4375 {(1 - \frac{8}{100})}^{2} = 4375 \times \frac{23}{25} \times \frac{23}{25} = 7 \times 23 \times 23 = 3703$
Hence, the number of patients in 2003 was 3703.

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