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Question

In the Young's double slit experiment the distance between two slits S1 and S2 is d. Interference pattern is obtained by these slits on a screen distant D from the slits. A dark fringe is produced at point P just in front of S1, The wavelength of light used is :

A
λ=D d2
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B
λ= d2D
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C
λ=Dd
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D
λ= dD
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Solution

The correct option is B λ= d2D
Path difference is D2+d2D=λ2 (as dark fringe is formed )
so ,
D(1+dD)12D=λ2
D+d22DD=λ2
λ=d2D
option B is correct

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