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Byju's Answer
Standard XII
Chemistry
First Order Reaction
In this case ...
Question
In this case we have
A
→
B
+
C
Time t
∞
Total
p
r
e
s
s
r
P
2
P
3
Find k?
A
k
=
1
t
l
n
P
3
2
(
P
3
−
P
2
)
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B
k
=
1
t
l
n
P
3
2
(
P
3
+
P
2
)
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C
k
=
1
t
l
n
P
2
2
(
P
3
−
P
2
)
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D
k
=
1
t
l
n
P
2
2
(
P
3
+
P
2
)
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Solution
The correct option is
A
k
=
1
t
l
n
P
3
2
(
P
3
−
P
2
)
Let P be the initial pressure of A and x be the change in the pressure of A to reach equilibrium.
When time
t
=
∞
P
=
P
3
2
When time is t, the total pressure
P
−
x
+
x
+
x
=
P
+
x
=
P
2
x
=
P
2
−
P
=
P
2
−
P
3
2
P
−
x
=
P
3
2
−
[
P
2
−
P
3
2
]
=
P
3
−
P
2
k
=
1
t
l
n
P
P
−
x
k
=
1
t
l
n
P
3
2
(
P
3
−
P
2
)
k
=
1
t
l
n
P
3
2
(
P
3
−
P
2
)
Suggest Corrections
0
Similar questions
Q.
In this case, we have (Consider it as a first-order reaction)
A
→
B
+
C
Time
t
∞
Total pressure
p
2
p
3
Then
k
is:
Q.
A
⇌
B
+
C
Time
t
∞
Total pressure of
(
B
+
C
)
P
2
P
3
Find equilibrium constant
k
.
Q.
A
→
B
+
C
Time t
∞
Total pressure of (A+B+C)
P
2
P
3
Then k is :
Q.
Subtract
1
−
p
3
from
2
p
3
−
3
p
q
2
−
2
q
3
Q.
If in a triangle
A
B
C
,
a
,
b
,
c
are in A.P. and
p
1
,
p
2
,
p
3
are the altitudes from the vertices
A
,
B
,
C
respectively then
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