In this figure AOB is a quarter circle of radius 10 and PQRO is a rectangle of perimeter 26. The perimeter of the shaded region is
A
13+5π
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B
17+5π
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C
7+10π
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D
7+5π
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Solution
The correct option is B17+5π Since AOB is the quarter circle the radius of AOB circle has length (2π(10)4)=5π Given QO=10 QO=RP=10 Since QO is the radius RP also equals Perimeter =26 262=13=PO+RO 10+10=20 20−13=7 BR+AP=7 5π+10+7=5π+17