Question

The hybridization of carbon 1, 2, 3, and 4 respectively are:

${\mathrm{C}}^1{\mathrm{H}}_2={\mathrm{C}}^2={\mathrm{C}}^3\mathrm{H}-{\mathrm{C}}^4{\mathrm{H}}_3$

• A. ${\mathrm{sp}}^2,\mathrm{sp},{\mathrm{sp}}^2,{\mathrm{sp}}^3$
• B. ${\mathrm{sp}}^2,{\mathrm{sp}}^2,{\mathrm{sp}}^2,{\mathrm{sp}}^3$
• C. ${\mathrm{sp}}^2,{\mathrm{sp}}^3,{\mathrm{sp}}^2,{\mathrm{sp}}^3$
• D. ${\mathrm{sp}}^3,\mathrm{sp},{\mathrm{sp}}^3,{\mathrm{sp}}^3$

Answer 1

The correct option is A

${\mathrm{sp}}^2,\mathrm{sp},{\mathrm{sp}}^2,{\mathrm{sp}}^3$

Explanation of correct option:

The correct option is A:

${\mathrm{C}}^1{\mathrm{H}}_2={\mathrm{C}}^2={\mathrm{C}}^3\mathrm{H}-{\mathrm{C}}^4{\mathrm{H}}_3$

1. In ${\mathrm{C}}^1$, carbon is attached to three different atoms, so its hybridisation will be ${\mathrm{sp}}^2$.
2. In ${\mathrm{C}}^2$, carbon is attached to two different atoms, so its hybridisation will be $\mathrm{sp}$.
3. In ${\mathrm{C}}^3$, carbon is attached to three different atoms, so its hybridisation will be ${\mathrm{sp}}^2$.
4. In ${\mathrm{C}}^4$, carbon is attached to four different atoms, so its hybridisation will be ${\mathrm{sp}}^3$.
5. So, the correct option is A.

The above explanation is matches with option A, thus there is no need to explain the incorrect option because they do not match with the explanation.