Question

In this multiplication question the five letters represent five different digits. What are the actual figures? There is no zero.
$\begin{array}{c}SEAM\\ T\\ \_\_\_\_\_\_\_\_\\ MEATS\end{array}$

• A. $M=3,E=9,A=7,T=4,S=8$
• B. $M=3,E=9,A=7,T=8,S=4$
• C. $M=4,E=3,A=9,T=7,S=8$
• D. $M=4,E=9,A=3,T=7,S=8$

Answer 1

Answer: (B)

$M=3,E=9,A=7,T=8,S=4$

From the information given in the question we know that when $M,T$ are multiplied, it leaves $S$ in the units place
$\to$ Using this infor we can eliminate option $A$ as in that option when $M(=3),T(=4)$ are multiplied, it leaves $2$ in the units place and not $8\left(S\right)$

$\to$ This condition holds true in the other options

Now if $A,T$ are multiplied and the carry over from the multiplication of $M,T$ is added, the end result must leave T in the units place
$\to$ Using this information we can eliminate answer options $C,D$ as well

$\circ$ In option $C$ multiplication of $M(=4),T(=7)$, gives a carry over of $2$, which when added to $3$ (the units digit of multiplication between $A(=9),T(=7)$) gives $5$ in the units place and not $7\left(T\right)$

$\circ$ Similarly in option $D$ multiplication of $M(=4),T(=7)$, gives a carry over of $2$, which when added to $1$ (the units digit of multiplication between $A(=3),T(=7)$) gives $3$ in the units place and not $7\left(T\right)$

Hence the answer is option $B$