In this questionIn a triangle ABC - AB - AC - AD is perpendicular to BC- prove that AB 2- AC 2- BD 2- CD 2I have done it like thisIn triangle ABDAD2- - AB - BD2- EQUATION 1In triangle ADCAD2 - ACZ -CD2- EQUATION 2an combining- EQUATION 1 and 2AD2 - AB2- - BD 2AD 2- ACZ - CD 2AB2 - AC2 - BD2-CD2bence arverIS THIS CORRECT

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In this question
In a triangle ABC , AB>AC , AD is perpendicular to BC , prove that
AB 2 - AC^{2 _{= BD 2= CD2}
_{I have done it like this
In triangle ABD
AD2. = AB2 -. BD2. EQUATION 1
In triangle ADC
AD2 =. AC2 - CD2. EQUATION 2
on combining. EQUATION 1 and 2
AD2 = AB2. -. BD 2
AD2 = AC2 - CD2.
AB2 -. AC2 =. BD2 - CD2
hence proved

IS THIS CORRECT}}

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