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In this reaction, 2Al+3/2O2----> Al2O3, 9grams of Al will react, with

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Dear student,

Q:-In this reaction 2Al+3/2O2 formed Al2O3 ,9 gm of Al will react with how many gm of O2?

Answer:- Chemical Reaction: 2Al + 3/2 O2 ---> Al2O3

From the above chemical reaction, we can say that, 2 moles or 54 g of aluminium requires 3/2 moles or 48 g of O2.

Then, 9 grams of Aluminium will require = (48/54) x 9 = 8 grams of O2.
Regards,

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