Dear student,
Q:-In this reaction 2Al+3/2O2 formed Al2O3 ,9 gm of Al will react with how many gm of O2?
Answer:- Chemical Reaction: 2Al + 3/2 O2 ---> Al2O3
From the above chemical reaction, we can say that, 2 moles or 54 g of aluminium requires 3/2 moles or 48 g of O2.
Then, 9 grams of Aluminium will require = (48/54) x 9 = 8 grams of O2.
Regards,