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Byju's Answer

Standard XII

Physics

Electric Generator

In Thomsons m...

Question

In Thomsons method, electric field of intensity $E$ , magnetic field of induction $B$ and velocity $V$ of the electrons were in mutually perpendicular directions. The condition for velocity is

V = E / B

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V = B / E

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V = B E

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V = \sqrt{B / E}

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Solution

The correct option is A $V = E / B$
Force Balance -
$Q E = Q v B$
$v = E / B$

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In Thomsons method, electric field of intensity E, magnetic field of induction B and velocity V of the electrons were in mutually perpendicular directions. The condition for velocity is

The correct option is A V=E/BForce Balance -QE=QvBv=E/B

In Thomsons method, electric field of intensity $E$ , magnetic field of induction $B$ and velocity $V$ of the electrons were in mutually perpendicular directions. The condition for velocity is

The correct option is A $V = E / B$
Force Balance -
$Q E = Q v B$
$v = E / B$