Question

In throwing a pair of dice, the probability of getting a doublet is
$\left(\frac{p}{q}\right),$ then the value of $|p-q|$ is

Answer 1

Total number of elements in sample space $S$ is $36.$
Let event $A=$ getting a doublet.
$A=\left\{\right(1,1),(2,2),(3,3),(4,4),(5,5),(6,6\left)\right\}$
$\therefore P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{6}{36}=\frac{1}{6}$