wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In throwing a pair of fair dice, find the probability of getting a total of 8.

A
3136
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
536
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
736
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2936
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 536
When a pair of dice is thrown the sample space consists
{(1, 1), (1, 2), ..., (1, 6)
(2, 1), (2, 2), ..., (2, 6)
..., ..., ...
..., ..., ...
..., ..., ...
(6, 1), (6, 2), ..., (6, 6)}
Note that (1,2) and (2, 1) are considered as separate points to make each outcome as equally likely.
To get a total of 8, favourable outcomes are, (2, 6) (3, 5) (4, 4) (5, 3) and (6, 2).
Hence required probability=536

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Elementary Event
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon