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Question
In throwing a pair of fair dice, find the probability of getting a total of 8.
In throwing a pair of fair dice, find the probability of getting a total of 8.
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Solution
The correct option is B 536
When a pair of dice is thrown the sample space consists
{(1, 1), (1, 2), ..., (1, 6)
(2, 1), (2, 2), ..., (2, 6)
..., ..., ...
..., ..., ...
..., ..., ...
(6, 1), (6, 2), ..., (6, 6)}
Note that (1,2) and (2, 1) are considered as separate points to make each outcome as equally likely.
To get a total of ′8′, favourable outcomes are, (2, 6) (3, 5) (4, 4) (5, 3) and (6, 2).
Hence required probability=536
When a pair of dice is thrown the sample space consists
{(1, 1), (1, 2), ..., (1, 6)
(2, 1), (2, 2), ..., (2, 6)
..., ..., ...
..., ..., ...
..., ..., ...
(6, 1), (6, 2), ..., (6, 6)}
Note that (1,2) and (2, 1) are considered as separate points to make each outcome as equally likely.
To get a total of ′8′, favourable outcomes are, (2, 6) (3, 5) (4, 4) (5, 3) and (6, 2).
Hence required probability=536
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