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Byju's Answer

Standard XII

Mathematics

Mutually Exclusive Events

In throwing o...

Question

In throwing of a die, let $A$ be the event 'even number turns up', $B$ be the event 'an odd prime turns up' and $C$ be the event 'a number less than $4$ turns up'. The events A, B and C form an exhaustive system.

True

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False

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Solution

The correct option is A True
$A \equiv {2, 4, 6}, B \equiv {3, 5}$ and $C \equiv {1, 2, 3} .$
Clearly $A \cup B \cup C = {1, 2, 3, 4, 5, 6} .$ Hence the system of events is exhaustive.

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In throwing of a die, let A be the event 'even number turns up', B be the event 'an odd prime turns up' and C be the event 'a number less than 4 turns up'. The events A, B and C form an exhaustive system.

The correct option is A TrueA≡{2,4,6},B≡{3,5} and C≡{1,2,3}.Clearly A∪B∪C={1,2,3,4,5,6}. Hence the system of events is exhaustive.

In throwing of a die, let $A$ be the event 'even number turns up', $B$ be the event 'an odd prime turns up' and $C$ be the event 'a number less than $4$ turns up'. The events A, B and C form an exhaustive system.

The correct option is A True
$A \equiv {2, 4, 6}, B \equiv {3, 5}$ and $C \equiv {1, 2, 3} .$
Clearly $A \cup B \cup C = {1, 2, 3, 4, 5, 6} .$ Hence the system of events is exhaustive.