In tossing a coin 10 times, the outcomes are

H, H, H, T, H, T, T, T, H, H

The empirical probability of getting a head is (in decimal form)

__

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Solution

Empirical probability = $\frac{n u m b e r o f t r i a l s i n w h i c h e v e n t h a p p e n e d}{t o t a l n u m b e r o f t r i a l s}$ = $\frac{6}{10}$ = 0.6

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When a coin tossed 10 times, the following outcomes are noted

H, H, H, T, H, T, T, T, H, H

The empirical probability of getting a head is (in decimal form)

When a coin tossed 10 times, the following outcomes are noted: H, H, H, T, H, T, T, T, H, H. The empirical probability of getting a head is

Q. A coin is tossed

400

times and the data of outcomes is below:

Outcomes	$H$	$T$
Frequency	$280$	$120$

Find:

(i) $P (H)$ , i.e., probability of getting head

(ii) $P (T)$ , i.e., probability of getting tail.

(iii) The value of $P (H) + P (T)$ .

A coin is tossed $150$ times and the outcomes are recorded. The frequency distribution of the outcomes $H$ (i.e., head) and $T$ (i.e., tail) is given below :

Outcome	$H$	$T$
Frequency	$85$	$65$

Find the value of $P (H)$ , i.e., probability of getting a head in a single trial.

A two-faced fair coin has its faces designated as head (H) and tail (T). This coin is tossed three times in succession to record the following outcomes: H.H.H. If the coin is tossed one more time, the probability (up to one decimal place) of obtaining H again given the previous realizations of H, H and H. would be

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In tossing a coin 10 times, the outcomes are H, H, H, T, H, T, T, T, H, H The empirical probability of getting a head is (in decimal form) __

Empirical probability = number of trials in which event happenedtotal number of trials = 610 = 0.6

In tossing a coin 10 times, the outcomes are

H, H, H, T, H, T, T, T, H, H

The empirical probability of getting a head is (in decimal form)

__

Empirical probability = $\frac{n u m b e r o f t r i a l s i n w h i c h e v e n t h a p p e n e d}{t o t a l n u m b e r o f t r i a l s}$ = $\frac{6}{10}$ = 0.6