Question

In tossing a fair coin twice, find the probability of getting two tails

• A. $\frac{1}{4}$
• B. $\frac{5}{6}$
• C. $\frac{2}{3}$
• D. $\frac{1}{2}$

Answer 1

The correct option is A $\frac{1}{4}$

In tossing a coin twice, the sample space, $S=HH,HT,TH,TT$
Therefore, $n\left(S\right)=4$
Let $A$ be the event of getting two tails.
$A=TT$

Therefore, $n\left(A\right)=1$
$P\left(A\right)=$ $\frac{n\left(A\right)}{n\left(S\right)}=\frac{1}{4}$