In transferring 1.5 C charge through a wire, 9 J of work is needed. Find the potential difference across the wire.

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Solution

$P o t e n t i a l d i f f e r e n c e (V) = \frac{w o r k d o n e (W)}{c h a r g e (q)}$
Or, $V = 9 1.5 = 6 v o l t .$

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In transferring 1.5 C charge through a wire, 9 J of work is needed. Find the potential difference across the wire.

Potential difference(V)=work done(W)charge(q) Or,V=91.5=6volt.

$P o t e n t i a l d i f f e r e n c e (V) = \frac{w o r k d o n e (W)}{c h a r g e (q)}$
Or, $V = 9 1.5 = 6 v o l t .$