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Hydrogen Peroxide

In transformi...

Question

In transforming 0.01 mole of $P b S$ to ${P b S O}_{4}$ , the volume of '10 volume' $H_{2} O_{2}$ required will be

11.2 mL

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22.4 mL

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33.6mL

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44.8 mL

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Solution

The correct option is D 44.8 mL
$P b S + 4 H_{2} O_{2} ⟶ P b {S O}_{4} + 4 H_{2} O$
From the above equation
$∵$ 1 mole of $P b S$ required 4 moles of $H_{2} O_{2}$
Weight of 0.04 mole $H_{2} O_{2} = 1.36 g$

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