Question

In trapezium $ABCD,AB=16cm,CE=4cm$ and the area of trapezium $=50c{m}^2$. Find $CD$.

• A. $5cm$
• B. $9cm$
• C. $10cm$
• D. $12cm$

Answer 1

The correct option is B

$9cm$

Let $CD$ be $x$.

Area of trapezium $=\frac{1}{2}\times$ (sum of parallel sides) $\times$ (distance between parallel sides)

$\Rightarrow$ Area of trapezium $ABCD=\frac{1}{2}\times (AB+CD)\times CE=50$

$\Rightarrow \frac{1}{2}\times (16+x)\times 4=50$

$\Rightarrow (16+x)\times 2=50$

$\Rightarrow 16+x=\frac{50}{2}=25$

$\Rightarrow x=25-16=9cm$

Hence, $CD=9cm$