Question

In trapezium ABCD, AB || CD, AB = 7 cm, CD = 5 cm and EF = 4 cm. Find the area of trapezium ABCD.

• A. 12 $c{m}^2$
• B. 24 $c{m}^2$
• C. 36 $c{m}^2$
• D. 48 $c{m}^2$

Answer 1

The correct option is B 24 $c{m}^2$

Given,
AB = 7 cm
CD = 5 cm and
EF = 4 cm.

Area of trapezium
= $\frac{1}{2}$$\times$(sum of parallel sides)$\times$height

Hence,
Area of trapezium ABCD
= $\frac{1}{2}\times (AB+CD)\times EF$
= $\frac{1}{2}\times (7+5)\times 4$
= $\frac{1}{2}\times 12\times 4$
= $6\times 4$
= 24 $c{m}^2.$