In trapezium ABCD, AB II CD. AB = 10 cm, CD = 7 cm, AD = 3 cm and BC = 3 cm. Find the approximate length of the perpendicular drawn from C to AB.

1 cm

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2.6 cm

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3.5 cm

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4 cm

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Solution

The correct option is B 2.6 cm
ABCD trapezium can be constructed by constructing a triangle and a parallelogram.
AB is the longest side of the trapezium. Take a point E on AB such that AE =7 cm and EB = 3 cm. EC = 3cm and CB= 3 cm. Now construct an Equilateral triangle with side 3cm. Construct the rest of the parallelogram. Now draw a perpendicular CF from vertex C to the side EB. Measure CF. CF will be 2.6 approximately.

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