In trapezium ABCD, AB II CD. AB = 10cm, CD = 7cm, AD = 3cm and BC = 3cm. Find the approximate length of the perpendicular drawn from C to AB.

1cm

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2.6cm

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3.5cm

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4cm

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Solution

The correct option is B 2.6cm
ABCD trapezium can be constructed by constructing a triangle and a parallelogram.
AB is the longest side of the trapezium. Take a point E on AB such that AE =7cm and EB = 3cm. EC= 3cm and CB= 3cm. Now construct an Equilateral triangle with side 3cm. Construct the rest of the parallelogram. Now draw a perpendicular CF from vertex C to the side EB. Measure CF. CF will be 2.6 approximately.

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